先序遍历
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> res;
stack<TreeNode*> s;
while(root != nullptr || !s.empty()){
while(root != nullptr){
s.push(root);
res.push_back(root->val);
root = root->left;
}
root = s.top();
s.pop();
root = root->right;
}
return res;
}
};
中序遍历
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
stack<TreeNode* > s;
while(root != nullptr || !s.empty()){
while(root != nullptr){ // 若有左节点一直入栈
s.push(root);
root = root->left;
}
root = s.top();
s.pop();
res.push_back(root->val);
root = root->right; // 访问右结点
}
return res;
}
};
后序遍历
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> postorderTraversal(TreeNode* root) {
vector<int> res;
if (root == nullptr) {
return res;
}
stack<TreeNode *> stk;
TreeNode *prev = nullptr;
while(root != nullptr || !stk.empty()){
while(root != nullptr){ // 若有左节点一直入栈
stk.push(root);
root = root->left;
}
root = stk.top();
stk.pop();
if(root->right == nullptr || root->right == prev){ //如果为叶子结点或者
res.push_back(root->val);
prev = root;
root = nullptr; // 去掉回溯 不然会一直循环
} else {
// 若有右结点则入栈(一层)
stk.push(root);
root = root->right;
}
}
return res;
}
};